miércoles, 22 de octubre de 2014

Prueba de escritorio



PRUEBA DE ESCRITORIO

S ≡ {{P, Q, R},  {¬P},  {P, Q, R}, {P, ¬Q}}

S ≡ {{P, Q, R}, {¬P}, {P, Q, R}, {P, ¬Q}, R1 (C1, C2) {Q, R}}

S ≡ {{P, Q, R}, {¬P}, {P, Q, R}, {P, ¬Q}, R1 (C1, C2) {Q, R}, R2 (C1, C4) {P, R}}

S ≡ {{P, Q, R}, {¬P}, {P, Q, R}, {P, ¬Q}, R1 (C1, C2) {Q, R}, R2 (C1, C4) {P, R}, R3 (C2, C4) {¬Q}}

S ≡ {{P, Q, R}, {¬P}, {P, Q, R}, {P, ¬Q}, R1 (C1, C2) {Q, R}, R2 (C1, C4) {P, R}, R3 (C2, C4) {¬Q}, R4 (C5,  C7) {R}}

CONSISTENTE

domingo, 12 de octubre de 2014

tablas de verdad


1)

p
^
q
^
¬
r
v
¬q
^
¬p
r
1
1
1
0
0
1
1
0
0
0
1
1
1
1
1
1
1
0
0
0
1
0
1
0
1
0
0
0
0
1
1
1
0
0
1
1
1
0
0
0
0
0
1
1
0
0
1
0
0
0
1
0
0
1
1
0
0
1
1
1
0
0
1
0
1
0
0
0
0
1
0
0
0
0
0
0
0
1
1
1
0
1
1
1
0
0
0
0
0
0
1
1
0
1
0
0

es satisfactible.
2)

p
r
P →(p v q)
P v q
P → q
(p v q) ^  (p →q)
P v ¬q
(p → q) →(p ^ q)
P ↔ q
(p ^ q)
(p → q) → ¬p
[( p → q) →¬p] ^ ( p v q)
[(p→
q) →
(p ^ q)
]→ ¬p
(¬p ^ q)
(p v q) → ¬q
(p v ¬q )  (p ↔ q)
¬p ^ ¬q
(p ^ q) ^ [(p → q)→ ¬p]
1
1
1
1
1
1
1
1
1
1
0
0
0
0
0
0
0
0
0
1
1
1
1
1
0
0
0
0
1
1
1
1
0
0
0
0
1
0
1
1
0
0
1
1
0
0
1
1
0
0
1
1
0
0
0
0
1
0
1
0
1
0
1
0
1
0
1
0
1
0
1
0